Skip to content

Dual (or biorthogonal) bases


While I was reading the paper, Life Beyond Bases: The Advent of Frames (Part I), I noticed a new and important word dual or biorthogonal bases.

Where does dual base come from?

  • A simple example

Consider b_1,b_2 are two independent vectors in R^2. Then b_1, b_2 is a base. Now consider an arbitrary vector x, it can be written as

x=c_1 b_1 +c_2 b_2

My question is how to compute c_1, c_2. The conventional answer is easy. Let c=[c_1,c_2]^T, B=[b_1,b_2], then x=Bc, so the coefficients are c=B^{-1}x. There is no difficulty to get the coefficients. But can we go a little further?

  • Go a little further

We already know x=Bc and c=B^{-1}x. Hence of course x=Bc=BB^{-1}x. Write B^{-1}=\tilde{B}=[\tilde{b_1}, \tilde{b_2}]^T. So we have


  • Summary

Given a base b_1,b_2 and an arbitrary vector x, then


where [\tilde{b_1}, \tilde{b_2}] is the dual base. Note \tilde{b_1}^Tx is the projection length of x on the basis $\tilde{b_1}$. And \tilde{b_i}^Tb_j=0, \tilde{b_i}^Tb_i=1. x can also be written as


We know [b_1,b_2][\tilde{b_1},\tilde{b_2}]^T=I. For a orthogonal base, the dual base is itself. Then


No comments yet

Leave a Reply

Please log in using one of these methods to post your comment: Logo

You are commenting using your account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )


Connecting to %s

%d bloggers like this: